I suspect that you are given the coefficient of friction for waxed skis on snow. You'll need it.zelda1850 said:oh but is there a way to solve this problem?
You are correct that a realistic answer would depend on the how the force of the poles is exerted and would be periodic. But this is meant as a simple problem, so just pretend that the poles only push backwards with no vertical component and that the force is continuously applied. Then the problem is easily solved (albeit naively).DmplnJeff said:With friction this is a far more complex question than we are given data for. We would need to know not only the coefficient of friction for the skis, but also data on the poles such as the angle at which they push off the ground since this would lighten the force on the skis. Ideally this would be related as a periodic function of time.
What's the acceleration of the skier?zelda1850 said:im not sure what the net force on the skier is
The velocity is constant thus the acceleration is zero. So what does that tell you about the net force?zelda1850 said:the acceleration is at constant so its zero
Good. Now answer my other question: What forces act on the skier?zelda1850 said:the net force is zero?
The horizontal component of the force pushing an object forward is the force that acts in the direction of motion, parallel to the surface on which the object is moving. It is also known as the tangential force.
The horizontal component of force can be calculated using trigonometric functions, specifically cosine, in conjunction with the magnitude of the force and the angle at which it is acting. The formula is Fcosθ, where F is the magnitude of the force and θ is the angle between the force and the horizontal direction.
The horizontal component of force is important because it helps determine the overall motion of an object. When the horizontal component of force is greater than the opposing forces, the object will accelerate in the direction of motion. It is also essential in calculating the work done on an object.
The horizontal component of force directly affects an object's velocity by accelerating or decelerating it in the direction of motion. If the horizontal component of force is equal to the opposing forces, the object will maintain a constant velocity. If it is greater, the object's velocity will increase, and if it is smaller, the object's velocity will decrease.
Yes, the horizontal component of force can be negative. This means that the force is acting in the opposite direction of motion, causing the object to decelerate. It is essential to pay attention to the sign of the force when calculating the horizontal component to accurately determine its effect on an object's motion.