What is the hybridization of C in R - N=C=O

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SUMMARY

The hybridization of carbon in the isocyanate group (R - N=C=O) is definitively sp. This conclusion is based on the fact that carbon is bonded to two atoms (nitrogen and oxygen) and has no lone pairs, which aligns with the characteristics of sp hybridization. The presence of two double bonds contributes to the formation of pi bonds through unhybridized p-orbitals, while the carbon also forms two sigma bonds. This information is crucial for users of the molsym program requiring accurate input values.

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R - N=C=O is the isocyanate group.

I have been trying to use a molsym program and it requires that value as input? The starting value is important. Thanks for any info.
 
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The carbon is sp-hybridized.
 
Well, thanks for the response but I cannot decide whether you are simply guessing or not. Do you have any reason that supports your response? Thanks
 
Carbons bound to two atoms and containing no lone pairs are sp hybridized.
 
Pi bonds are made by sharing the unhybridized p-orbitals. Carbon in this case has two double bonds, containing one pi bond each, while also having two sigma bonds - one with Nitrogen and the other with Oxygen. Therefore, the hybridization is sp with 2 unhybridized p orbitals.
 
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