What is the identity for coplanar, non-collinear vectors?

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The discussion centers on the identity involving coplanar, non-collinear vectors, specifically the relationship expressed as αa + βb + γc = 0 leading to α + β + γ = 0. Participants clarify that if vectors a, b, and c are coplanar, they are linearly dependent, meaning any third vector can be expressed as a linear combination of two basis vectors. The identity holds true under the condition that the vectors are coplanar, and the confusion arises from misinterpretations regarding the coefficients of the vectors.

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atavistic
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I kinda remember some identity which goes as follows:

If a,b,c are coplanar, non collinear vectors then

\alpha a + \beta b + \gamma c = 0
=> \alpha + \beta + \gamma = 0

or something like this. Can someone help me remember.
 
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Well, this isn't quite correct.

If a, b, and c are three coplanar vectors, they are for sure linearly dependent in the plane, since, if a, b are two non colinear non zero vectors in a plane, they form a basis, i.e. \alpha a + \beta b = 0 => \alpha = \beta = 0. Every third vector can be representet uniquely as a linear combination of the basis vectors a and b.
 


atavistic said:
I kinda remember some identity which goes as follows:

If a,b,c are coplanar, non collinear vectors then

\alpha a + \beta b + \gamma c = 0
=> \alpha + \beta + \gamma = 0

or something like this. Can someone help me remember.

You need to replace "a, b, and c are coplanar" by "a, b, and c are NOT coplanar".
 


radou said:
Well, this isn't quite correct.

If a, b, and c are three coplanar vectors, they are for sure linearly dependent in the plane, since, if a, b are two non colinear non zero vectors in a plane, they form a basis, i.e. \alpha a + \beta b = 0 => \alpha = \beta = 0. Every third vector can be representet uniquely as a linear combination of the basis vectors a and b.

Also for coplanar vectors
a\cdot(b\times c)= 0
 


I am sorry but I really mean \alpha + \beta + \gamma = 0 and not \alpha = \beta =\gamma = 0
 


atavistic said:
I am sorry but I really mean \alpha + \beta + \gamma = 0 and not \alpha = \beta =\gamma = 0

Well, if \alpha = \beta =\gamma = 0, then most certainly \alpha + \beta + \gamma = 0. :wink:
 


atavistic said:
I kinda remember some identity which goes as follows:

If a,b,c are coplanar, non collinear vectors then

\alpha a + \beta b + \gamma c = 0
=> \alpha + \beta + \gamma = 0

or something like this. Can someone help me remember.

mathman said:
You need to replace "a, b, and c are coplanar" by "a, b, and c are NOT coplanar".
No, if they were not coplanar, that statement would not be true.
 


HallsofIvy said:
No, if they were not coplanar, that statement would not be true.

In his original statement he had all coef = 0, not the sum. Obviously changing the question would usually lead to a change in the response.
 


Oh, thanks. I hate it when people edit their post after there have been responses!
 

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