What is the Impact of k on Wave Behavior and Its Physical Significance?

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Homework Help Overview

The discussion revolves around the impact of the complex quantity k on the behavior of a light wave represented by an exponential function. The original poster attempts to understand how the substitution of n with n-ik influences the wave's characteristics and its physical significance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the mathematical manipulation of the wave equation, questioning the implications of the k term and its effect on the wave's behavior. There is a focus on identifying the type of wave resulting from the substitution and its characteristics.

Discussion Status

Some participants have provided insights into the nature of the wave, suggesting it may be dampened and discussing how variations in k affect the rate of decay. However, there is no explicit consensus on the overall significance or interpretation of these findings.

Contextual Notes

The discussion is constrained by the need for clarity on the physical significance of k and the assumptions underlying the wave representation. Participants are navigating through mathematical interpretations without definitive conclusions.

Wishbone
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The problem gives the angular frequency of a light wave (w) is represented by


e^iw(t-nx/c)

it says that sometimes n is replaced by the complex quantity n-ik.

The question asks what is the effect of k on the wave. Also, it asks, what is its physical significance?


I tried substituting in for n-ik for n, and then multiplying in the iw.


I got: e^ (iwt-iwnx +kx)/c

So I see that the k term is the only real term in the exponent, however I am not sure how that effects the wave, or what its physical significance is.
 
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I don't think that is correct. Doing the calculations, I get, after putting into an illuminating form:

[tex]e^{-kx/c}e^{i(wt-nx/c)}[/tex]

What kind of a wave is that? (i.e. what is the effect of k on the wave?)
 
thats a dampened wave, isn't it?
 
and the larger the K, the quicker the wave dies?
 
yep.

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sweet, thanks dude.
 

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