What is the impedance of a tank circuit at resonance?

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SUMMARY

The impedance of a tank circuit at resonance is determined by the relationship between the inductor (L) and capacitor (C) values. At resonance, where \(\omega = \frac{1}{\sqrt{LC}}\), the impedance (Z) approaches infinity due to the phase difference between the current in the capacitor and inductor. The correct formula for impedance is \(Z = \frac{L}{C(j\omega L - \frac{j}{\omega C})}\). Substituting the resonant frequency into the impedance equation results in Z equating to zero, indicating that the circuit behaves as a short circuit at resonance.

PREREQUISITES
  • Understanding of tank circuits and resonance
  • Familiarity with complex impedance and phasors
  • Knowledge of the relationships between inductance (L), capacitance (C), and frequency (\(\omega\))
  • Ability to manipulate complex equations in electrical engineering
NEXT STEPS
  • Study the derivation of impedance in RLC circuits
  • Learn about the effects of damping in tank circuits
  • Explore the concept of quality factor (Q) in resonant circuits
  • Investigate the applications of tank circuits in radio frequency (RF) design
USEFUL FOR

Electrical engineers, physics students, and anyone studying circuit theory or resonance in RLC circuits will benefit from this discussion.

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Homework Statement



btSCjl.jpg


a) Determine the impedance of this circuit.
b) What is the impedance when \omega = \frac{1}{\sqrt{LC}}


Homework Equations





The Attempt at a Solution



I think I have part a:
Z = j({\omega}C - \frac{1}{{\omega}C})

EDIT: I got the Z wrong. It's Z = \frac{L}{C(j{\omega}L - \frac{j}{{\omega}C})}

[STRIKE]For part b, I'm getting that Z = 0 simply by substituting in \omega.
Is this correct? [/STRIKE]

This gives an impedance of \infty

I feel more confident is this answer. I'm guessing that the current in the capacitor and inductor are out of phase by \pi causing what appears to be an infinite impedance. I'm still curious as to the exact reason though, if anyone could lend help. Thanks!
 
Last edited:
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Y = jwC - j/wL = j(wC - 1/wL) = j(w^2LC - 1)/wL

Z= 1/Y = jwL/(1 - w^2LC)
 

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