mathguyz
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Does anyone here know what the indefinite integal of 1/e^x is?
Im an new member and, this is my first post.
Im an new member and, this is my first post.
The discussion revolves around finding the indefinite integral of the function 1/e^x. Participants explore different approaches to solving the integral, including substitution methods and direct integration techniques.
There is no consensus on the best method to approach the integral, as participants present different techniques and reasoning. Some suggest substitution is unnecessary, while others advocate for it to aid understanding.
The discussion includes various assumptions about the original poster's familiarity with integration techniques, which may affect the clarity of the proposed solutions.
mathguyz said:Does anyone here know what the indefinite integal of 1/e^x is?
Im an new member and, this is my first post.
sutupidmath said:here it is how you might want to think about it: i am assuming you know how to integrate this, since it is only a tabelar integral
[tex]\int e^{x}dx[/tex], for the other one[tex]\int e^{-x}dx[/tex], take the substitution -x=t, so now we have dx=-dt, now substitute back on the integral we get:
[tex]\int e^{t}(-dt)=-\int e^{t}dt=-e^t+c[/tex] substituting back for the original variable we get [tex]-e^{-x}+c[/tex]
JasonRox said:Why not just let u = e^-x?
No need for substitution here.