What Is the Index of Refraction for a Transparent Plastic Piece?

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SUMMARY

The discussion focuses on calculating the index of refraction for a transparent plastic piece using Snell's Law, represented by the equation ni * sin(theta,i) = nr * sin(theta,r). The user assumes the index of refraction for air (ni) is 1 and attempts to solve for the index of refraction of the plastic (nr) using the formula nr = ni * sin(theta,i)/sin(theta,r). However, the solution is incorrect, likely due to a mix-up in the angles of incidence and refraction or incorrect angle measurements from the normal.

PREREQUISITES
  • Understanding of Snell's Law and its application in optics
  • Knowledge of angle measurement in relation to the normal line
  • Familiarity with the concept of the index of refraction
  • Basic trigonometry for calculating sine values
NEXT STEPS
  • Review the principles of Snell's Law in optics
  • Learn how to accurately measure angles in refraction problems
  • Explore examples of calculating the index of refraction for various materials
  • Study the effects of different incident angles on refraction
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of light refraction and index of refraction calculations.

smashyash
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Homework Statement



I'm not sure if this can be answered without the picture but I can't get it posted.
The problem gives theta(incident) and theta(r). It's a basic refraction through a transparent plastic piece. It askes for the index of regraction of this material.

Homework Equations



ni * sin(theta,i) = nr * sin(theta,r)

The Attempt at a Solution



I figured since the don't give any more information that the ni value = 1 because it's assumed to be air. So I tried nr = ni * sin(theta,i)/sin(theta,r)
but this is not right...
 
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hi smashyash! :smile:

(have a theta: θ and try using the X2 icon just above the Reply box :wink:)
smashyash said:
I figured since the don't give any more information that the ni value = 1 because it's assumed to be air. So I tried nr = ni * sin(theta,i)/sin(theta,r)
but this is not right...

that looks right …

without seeing the diagram, I'm guessing that either your i and r are the wrong way round, or one or both of your θs are measured from the surface instead of from the normal :smile:
 

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