What Is the Initial Speed of a Block Given Friction and Distance?

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SUMMARY

The discussion focuses on calculating the initial speed of a block traveling 10 meters on a horizontal surface with a friction coefficient (\u03bc) of 0.40 before it comes to a stop. The relevant equations include the work-energy principle and the friction force equation, where the friction force (f) is defined as f = \u03bc * N, with N being the normal force. Participants suggest starting with the net force equation, \u03a3F = ma, and relate acceleration to the gravitational constant (g) to solve for the initial speed.

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Homework Statement


Find the initial speed of a block which travels 10m along a horizontal surface if [tex]\mu[/tex]= 0.40 between the block and the surface before stopping.


Homework Equations


[tex]\Sigma[/tex]W = 1/2mvB2 - 1/2mvA2 + mgyB - mgyA

[tex]\Sigma[/tex]W = W * dAB * cos (W, dAB)

f = [tex]\mu[/tex]* N
N= mgsin[tex]\theta[/tex]

The Attempt at a Solution


so far i have:
[tex]\Sigma[/tex]W = 0
[tex]\Sigma[/tex]W = WN + WW + Wf

and

[tex]\Sigma[/tex]W = WW * dAB * cos (270)
[tex]\Sigma[/tex]W = WW * 10m * 0


not sure if I'm doing this right or where to go from here
 
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This problem requires an equation that you haven't included yet.

So we'll start with:
[tex]\Sigma[/tex]F = max
[tex]\Sigma[/tex]F = Px + fx + Nx + Wx
max = Px + fx+ Nx + Wx

[tex]\mu[/tex] = -a / g
Try to solve it from here.
 

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