What is the Input Torque for a Gearbox with Given Parameters?

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SUMMARY

The discussion focuses on calculating the input torque (T1) for a gearbox with a flywheel that accelerates from rest to 300 revolutions per minute in one minute, given an efficiency of 92%. The user calculated the output power as 115.66 W and the input power as 125.72 W, leading to an output torque (Tout) of 3.68 Nm. The user confirmed that the input torque can be derived by dividing the output torque by the efficiency ratio, thus resolving their query effectively.

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Homework Statement


A gearbox and flywheel are as shown in FIGURE 4. The output shaft rotates in the opposite direction to the input shaft at 5 times its speed. The gearbox has an efficiency of 92%. If the flywheel is solid, has a mass of 50 kg, a diameter of 1.5 m and is to accelerate from rest to 300 revs min –1 in 1 minute:

(a) Calculate the torque required at input T1.

(b) Calculate the magnitude and direction of the torque required to hold the gearbox stationary (holding torque Th ). Show the direction of the holding torque applied to the shaft with the aid of a sketch

Homework Equations


efficiency = Pout/Pin = - ωout×Toutin×Tin

T1 + T2 + T3 = 0

The Attempt at a Solution


I've attached my working which includes values calculated for :

Powerout = 115.66 W
Powerin = 125.72 W
Tout = 3.68 Nm
Angular velocity α = 0.5236 rad/s2

The question is asking me for the input torque is it as simple as dividing output Torque by the efficiency ratio or have I missed out on another parameter? I know how to solve part B when I can calculate input Torque. Any assistance would be greatly appreciated thanks.

*I realize there's another thread posted about a year ago with the same question but it was asking for help on a different part which I've not got to yet.
 

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