What is the Impedance Value for a Circuit with Given Parameters?

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    Impedance Value
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Discussion Overview

The discussion revolves around calculating the impedance value (Z) for a circuit with given parameters, including resistance (R), voltage (Vs), and power factor (PF). The context is primarily homework-related, focusing on the application of electrical engineering principles.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents an initial calculation for current (I) and impedance (Z) but finds a discrepancy when checking against the power factor.
  • Another participant questions the value of power (P) used in the equations and suggests considering the power factor as related to the angle of the impedance, indicating an inductive reactance component.
  • A subsequent reply calculates the inductive reactance (XL) using trigonometric relationships and proposes a new impedance value based on this calculation.
  • Further replies express appreciation for the assistance and confirm that the new calculations seem more accurate.

Areas of Agreement / Disagreement

The discussion shows some progression in calculations, but there is no explicit consensus on the final impedance value, as participants are refining their approaches and calculations.

Contextual Notes

Participants reference earlier parts of the question and calculations, indicating dependencies on previous assumptions and values, particularly regarding power (P) and its role in determining current (I).

justadaftspark
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Homework Statement



Find Z R=10Ω
Vs=120v
(PF)=0.72 Lagging

Homework Equations



I=P/Vs(PF)
Z=Vs/I

The Attempt at a Solution






I have I=P/Vs(PF) and transpose for I to get 4.34A
Then to find Z Z=Vs/I which gives 27.65ohm
When I put this back into (PF)=R/Z to confirm i don't get the right answer


Any help would be great
 
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What value do you use for P in your equations?

As an alternative, consider that the power factor is the cosine of the angle of the apparent power phasor, and that the impedance will have the same angle. Here the PF is 0.72 and is said to be lagging, which means the impedance will appear to have an inductive reactance component. You can draw the triangle for the impedance:

attachment.php?attachmentid=59591&stc=1&d=1371387227.gif


You should be able to write an expression to relate XL to given cosine of the angle θ.
 

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Thanks for getting back, so

arcos( 0.72 ) = 43.95deg
Tanθ o/a
Tan 43.95 * XL/10 transpose for XL
XL = Tan 43.95*10 = 9.64 ohm
using trig Z^2 = R^2 + XL^2
= Drum roll..... 13.89 ohm

Does this seem closer to the mark? it works when i put it into a known equation

P was from a earlier part of the question which i used to find I

Thank you, its much appriciated
 
Looks good!
 
Awesome, Thanks a lot
 

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