What is the intensity of the transmitted light?

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SUMMARY

The intensity of transmitted light through two polarizers misaligned by 30° can be calculated using the correct form of Malus' Law: I = I0 * cos(theta)^2. Given an initial intensity (I0) of 3.86 W/m², the transmitted intensity (I) is computed as I = 3.86 * cos(30°)^2, resulting in an intensity of approximately 3.34 W/m². The initial misunderstanding stemmed from the incorrect application of Malus' Law, which requires squaring the cosine of the angle between the light's polarization direction and the polarizer's axis.

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Homework Statement


Two polarizers are out of alignment by 30°. If light of intensity 3.86 W/m2 and initially polarized halfway between the polarizing angles of the two filters passes through the two filters, what is the intensity of the transmitted light?


The Attempt at a Solution



Use Malus' law:

I = I0 * cos(theta)
which gives me 3.34 W/m2

but it's not right... any hints?
should i divide it by 2 since it says that it is polarized halfway between ?
 
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You have the wrong expression for Malus' law.
 
i forgot square

I = I0 * cos(theta)^2 other than that it's right
 
So how would you go about solving this now that you have the correct form of Malus' Law?
 

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