What Is the Key Step Missing in Deriving Wirtinger Derivatives?

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The discussion focuses on deriving the Wirtinger derivative, specifically the expression for ∂F/∂ȳ = 1/2(∂F/∂x + i ∂F/∂y). The user initially applies the chain rule but encounters an error in the partial derivatives of x and y with respect to ȳ. The correct approach involves recognizing the relationship between z and ȳ, leading to the correct expression. A critical typo is identified, where ȳ should be defined as ȳ = x - iy instead of ȳ = x + iy.

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Let [tex]\bar{z} = x+iy[/tex].
We are given that [tex]x = \frac{z+\bar{z}}{2}[/tex] & [tex]y = \frac{z-\bar{z}}{2i}[/tex].

We are trying to derive [tex]\partial F/\partial\bar{z} = 1/2(\partial F/ \partial x + i \partial F/ \partial y)[/tex], where F(x,y) is some function of two real variables.

Using the chain rule I get [tex]\partial F/\partial\bar{z} = \partial F/\partial x\cdot\partial x/\partial\bar{z} + \partial F/\partial y\cdot\partial y/\partial\bar{z}[/tex].
This is the point where I know something is going wrong.

I replace [tex]\partial x/\partial\bar{z}[/tex] with [tex]\partial \frac{z+\bar{z}}{2}/\partial\bar{z}[/tex], and the same for y with [tex]\frac{z-\bar{z}}{2i}[/tex].

Taking the partial derivatives [tex]\partial \frac{z+\bar{z}}{2}/\partial\bar{z}[/tex] & [tex]\partial \frac{z-\bar{z}}{2i}/\partial\bar{z}[/tex],
I get [tex]\partial F/\partial\bar{z} = \partial F/\partial x\cdot\frac{1}{2}-\partial F/\partial y\cdot\frac{1}{2i} = \frac{1}{2}(\partial F/\partial x - \partial F/i\partial y)[/tex].

What key step am I missing that's leading me to the wrong expression?
 
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paraboloid said:
Let [tex]\bar{z} = x+iy[/tex].
We are given that [tex]x = \frac{z+\bar{z}}{2}[/tex] & [tex]y = \frac{z-\bar{z}}{2i}[/tex].

We are trying to derive [tex]\partial F/\partial\bar{z} = 1/2(\partial F/ \partial x + i \partial F/ \partial y)[/tex], where F(x,y) is some function of two real variables.

Using the chain rule I get [tex]\partial F/\partial\bar{z} = \partial F/\partial x\cdot\partial x/\partial\bar{z} + \partial F/\partial y\cdot\partial y/\partial\bar{z}[/tex].
This is the point where I know something is going wrong.

I replace [tex]\partial x/\partial\bar{z}[/tex] with [tex]\partial \frac{z+\bar{z}}{2}/\partial\bar{z}[/tex], and the same for y with [tex]\frac{z-\bar{z}}{2i}[/tex].

Taking the partial derivatives [tex]\partial \frac{z+\bar{z}}{2}/\partial\bar{z}[/tex] & [tex]\partial \frac{z-\bar{z}}{2i}/\partial\bar{z}[/tex],
I get [tex]\partial F/\partial\bar{z} = \partial F/\partial x\cdot\frac{1}{2}-\partial F/\partial y\cdot\frac{1}{2i} = \frac{1}{2}(\partial F/\partial x - \partial F/i\partial y)[/tex].

What key step am I missing that's leading me to the wrong expression?

[tex]\frac{1}{2}(\partial F/\partial x - \partial F/i\partial y)= \frac{1}{2}(\partial F/\partial x + i \partial F/\partial y),[/tex]

so I think you derived the stated result. Incidentally, you have a typo at the top. With the definitions of x and y that you used, [tex]\bar{z} = x - i y.[/tex]
 

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