What is the Kinetic and Internal Energy of a Car-Truck Collision?

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SUMMARY

The discussion focuses on calculating the kinetic and internal energy of a car-truck collision involving a 1200 kg car moving at 88 km/h and a 7600 kg truck moving at 65 km/h. After the collision, both vehicles stick together and move at 68 km/h. The kinetic energy of the center of mass of the system is derived using the equation m1v1 + m2v2 = (m1 + m2)vf, while the internal energy before and after the collision is determined using the kinetic energy formula K = 1/2mv².

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with kinetic energy calculations
  • Knowledge of unit conversions (km/h to m/s)
  • Basic physics concepts related to collisions
NEXT STEPS
  • Calculate the kinetic energy of the car and truck before the collision using K = 1/2mv²
  • Determine the total kinetic energy of the system after the collision
  • Explore the concept of internal energy in inelastic collisions
  • Study momentum conservation in multi-object systems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of momentum and energy conservation in collision scenarios.

gmagnus
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Homework Statement



A 1200 kg car moving at 88 km/h collides with a 7600 kg truck moving in the same direction at 65 km/h. The two stick together, continuing in their original direction at 68 km/h. Determine the kinetic energy of the center of mass of the (car + truck) system. Determine the internal energy of the (car + truck) system before the collision. Determine the internal energy of the (car + truck) system after the collision.

Homework Equations



m1v1 + m2v2 = (m1 + m2)vf

Kinetic energy of a system is K = Kcm + Kint

K = 1/2mv2

The Attempt at a Solution



88 km/h converted to 24.4444 m/s
65 km/h converted to 18.0556 m/s
 
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You'd need to find the velocity of the (car+truck) system after collision to get the kinetic energy.
 

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