What is the Law Behind Earth's Force on Falling Objects?

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    Earth Falling Force
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Discussion Overview

The discussion revolves around the forces acting on falling objects, specifically the gravitational force exerted by the Earth and the nature of this force during free fall and impact. Participants explore concepts related to acceleration, force, and the laws governing these phenomena.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the nature of the force exerted by the Earth on falling objects and seeks to understand the law governing this force.
  • Another participant explains that when an object is dropped, it accelerates towards the ground at a rate of g, and discusses the deceleration upon impact using SUVAT equations.
  • A different participant emphasizes that force relates to the change in speed, noting that the same force applied for the same duration will result in the same change in speed regardless of the object's initial state.
  • Some participants clarify that the force being discussed is gravitational force, described by the formula F = Gm1m2/r², and point out the importance of understanding gravitational interactions.
  • There are technical discussions about the correct formatting of equations in the forum, indicating some confusion regarding the use of LaTeX syntax.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the initial question, with some clarifying concepts while others remain uncertain. There is no consensus on the interpretation of the original question or the specific laws being referenced.

Contextual Notes

Some participants appear to have different interpretations of the forces involved and the laws governing them, leading to a mix of explanations and clarifications without resolving the initial inquiry.

Hepic
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If we let a thing from a height,earth force that with F=m*a=m*g=B(weight).
BUT What is the power of earth,when the thing goes down(the power that force the thing at Earth too).I mean the different power,that keeps that in the ground. Logically the force of earth,is about the speed of thing,but what is the law?

Thank you!
 
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Not sure if I understand your question.

If you drop something it will accelerate towards the ground with a = g.

When it hits the ground it will penetrate a distance "s". You could calculate the acceleration (deceleration) that occurs when it hits the ground using a SUVAT equation such as..

V2 = U2 +2as

where

V is the final velocity = 0
U is the initial velocity (eg at impact with the ground)
S is the stopping distance (the distance it penetrates the ground)
a is the acceleration.

Then solve for "a"

More here. http://en.wikipedia.org/wiki/Equations_of_motion

If you want to know the average force during the impact you could apply F=ma.
 
Hi Hepic! :wink:

I'll just add this to what CWatters :smile: has said …
Hepic said:
Logically the force of earth,is about the speed of thing,but what is the law?

No, force is about change of speed …

the same force (applied for the same time) will increase the speed from 0 to 1, or from 100 to 101.

So the force is the same for a moving thing as for a stationary thing.

(and of course when something is on the ground, there are two forces on it, the weight mg down and the normal force mg up … so the total force is 0, and the change in speed is 0!)
 
Hepic said:
If we let a thing from a height,earth force that with F=m*a=m*g=B(weight).
BUT What is the power of earth,when the thing goes down(the power that force the thing at Earth too).I mean the different power,that keeps that in the ground. Logically the force of earth,is about the speed of thing,but what is the law?

Thank you!
I too didn't understand your question.
The force of Earth you are talking about is Gravity.Gravity exists between all masses and is given by the formula:

##F=\frac{Gm1m2}{r2}##http://en.wikipedia.org/wiki/Gravitation
 
Last edited:
hi adjacent! :smile:
adjacent said:
##F=\frac{Gm1m2}{r2}##

you can't use the SUB tags inside latex! :wink:
 
tiny-tim said:
hi adjacent! :smile:


you can't use the SUB tags inside latex! :wink:
Then how do I write that equation?

EDIT:test,
##F=\frac{Gm_1m_2}{r^2}##
 
Last edited:
F=\frac{Gm_1m_2}{r^2} …

##F=\frac{Gm_1m_2}{r^2}## :wink:
 
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