What is the Limit of a Complex Logarithmic Function in Calculus Homework?

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Homework Help Overview

The discussion revolves around evaluating the limit of a complex logarithmic function as x approaches 0, specifically involving the natural logarithm of a fraction that includes sine and polynomial expressions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the evaluation of the limit by substituting x=0 into the function. There are discussions about the complexity of the problem and the use of calculators, as well as the simplification of the expression to a more manageable form.

Discussion Status

The conversation has progressed with participants confirming the simplification of the limit expression. Some have expressed initial confusion, but guidance has been provided that led to a clearer understanding of the problem.

Contextual Notes

Participants mention constraints regarding the use of calculators and the challenge posed by the complexity of the problem, indicating a learning environment focused on understanding rather than simply obtaining answers.

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Homework Statement


I have this problem on my calculus homework:

[tex] \lim_{x \to 0} \ln\frac{(\sin(cos(x))(x^5+5x^4+4x^3+17)} {x^6+7x^5+8x^4+9x^3+16})[/tex]

Homework Equations



n/a

The Attempt at a Solution


I honestly have no idea how to go about this. We really haven't been shown anything like this in class, and the complexity of the problem is quite intimidating. I would be grateful for any sort of help.
 
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Try evaluating it at x=0 first.
 
I got a number like ln.0854, but that was with a calculator which I'm not allowed to use. Not sure how I would do it otherwise
 
Well, every x becomes 0, so your two polynomials reduce to 17 on the top and 16 on the bottom, respectively. Can you see the rest?
 
I have this.. is that all? Is there a way I can evaluate sin(1) without a calculator or do I leave as is?

[tex] <br /> \lim_{x \to 0} \ln\frac{(\sin(1)(17)}{16})<br /> [/tex]
 
Yes, you have it in perfectly reduced form.
 
That was a lot easier than it looked. I spent so much time trying to make it more complicated then it actually was. Thanks so much for your help.
 

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