What is the limit of a piecewise function with different equations at x=2?

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SUMMARY

The limit of the piecewise function g(x) at x=2 is determined by evaluating the left-hand limit and the right-hand limit. For x < 2, g(x) is defined as (x^2 - 3), which approaches 1 as x approaches 2. For x > 2, g(x) is defined as cos(x - 2), which also approaches 1 as x approaches 2. Therefore, the limit of g(x) as x approaches 2 is conclusively 1.

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Homework Statement



Find the limit-> 2 g(x)= (x^2-3) if x < 2
3 if x=2
cos(x-2) if x>2

Homework Equations



So, I know you basically ignore the limit at 2, and you need to check it from the right and left. So, you want the x^2-3 and cos(x-2) equations

The Attempt at a Solution



I plugged two in for x, in both of these equations (2^2-3)=1 and cos(2-2)=cos(0)=1

So wouldn't the answer be 1?
 
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JessicaJ283782 said:

Homework Statement



Find the limit-> 2 g(x)= (x^2-3) if x < 2
3 if x=2
cos(x-2) if x>2


Homework Equations



So, I know you basically ignore the limit at 2, and you need to check it from the right and left. So, you want the x^2-3 and cos(x-2) equations



The Attempt at a Solution



I plugged two in for x, in both of these equations (2^2-3)=1 and cos(2-2)=cos(0)=1

So wouldn't the answer be 1?

Yes, it would. Though you should be thinking 'the value of the functions approaches 1 as x->2' rather than saying 'I plugged in 2'.
 

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