What is the limit of the function [sqrt(x-1)] as x approaches 1?

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Homework Help Overview

The discussion revolves around the limit of the function \(\sqrt{x-1}\) as \(x\) approaches 1, specifically examining the behavior of left and right-hand limits and their definitions. Participants also consider a similar limit involving \(\sqrt{1-x}\).

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the definitions of left and right-hand limits, questioning the validity of results obtained from computational tools like Mathematica and Wolfram Alpha. There is discussion about the implications of complex numbers in the context of limits.

Discussion Status

There is an ongoing exploration of the definitions of limits and the implications of using complex analysis. Some participants express uncertainty about their understanding, while others affirm their interpretations of the limits as undefined based on their current knowledge.

Contextual Notes

Participants note that they have not been taught complex-valued functions, which influences their interpretations and submissions regarding the assignment.

khurram usman
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limit x-->1 of [sqrt(x-1)]

i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'
 
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khurram usman said:
i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'
You are correct in saying that for [itex]f:\mathbb{R}^+\mapsto\mathbb{R}^+[/itex], [itex]f:x\mapsto\sqrt{x}[/itex], the left-hand limit does not exist. However, Mathematica and Wolfram Alpha (and Maple, I would imagine as well as most CAS) will quite happily work in the complex plane, where the limit does exist and is indeed zero.
 
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yes you are right there.
on the graph one of the lines was marked as real and other as imaginary.
so it means as far as i have learned, my answer was correct. the limit for both the functions is un defined
 


khurram usman said:
so it means as far as i have learned, my answer was correct. the limit for both the functions is un defined
Both functions, there is only one function: the square root. The two lines on the graph indicate the values of the function (both the real and imaginary parts).
 


ok...but i have not been taught any complex valued functions yet.
so as far as my assingnment is concernerd i should submit this as undefined.
thanks a lot
 


khurram usman said:
so as far as my assingnment is concernerd i should submit this as undefined.
It would seem so, yes.
khurram usman said:
thanks a lot
No problem.
 

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