What is the limit of the sequence (Xn) = (n!)^(1/n)?

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The limit of the sequence (Xn) = (n!)^(1/n) diverges as n approaches infinity. To demonstrate this, one effective method is to apply Stirling's formula, which approximates factorials. By taking the logarithm of the sequence, specifically (1/n)log[n]!, and analyzing the sum of logarithms from 1 to n, it becomes evident that the sequence diverges. The bounds established for different ranges of n confirm the divergence behavior.

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steviet
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I'm working on the limit of the sequence
(Xn) = (n!)^(1/n)
Pretty sure it diverges as n goes to infinity,
but unsure how to show it.
Any hint would ge greatly appreciated.
 
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Your instincts are good. Take a log and use Stirling's formula. That's one way.
 
an elemetary proof is to take log so you get (1/n)log[n]! then you get [log1+Log2+log3...logn]/n

set bounds for 1<n<11 sum truncate terms
you get sum between 0 and 1

for 11<n<101 get sum between 10 and 20

you can see how this diverges
 

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