What is the logic behind L'Hopital's Rule?

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SUMMARY

L'Hopital's Rule provides a method for evaluating limits of indeterminate forms by using derivatives. The rationale behind the rule is rooted in the Taylor series approximations of functions, where both the numerator and denominator approach zero. By applying the first-order Taylor approximation, one can derive that the limit of the quotient of two functions is equivalent to the limit of the quotient of their derivatives. This understanding solidifies the logical foundation of L'Hopital's Rule as a valid mathematical shortcut.

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  • Understanding of limits in calculus
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Can anyone tell me, what is the rationale behind L'Hopital's Rule? I just know that how to use it but don't know why it is logic.
 
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its not any logic ... it has good enough proof ...
try proving it if u want ... shouldn't be hard ...
it should give u a good rundown on all the properties of limits :)

-- AI
 
CartoonKid said:
Can anyone tell me, what is the rationale behind L'Hopital's Rule? I just know that how to use it but don't know why it is logic.

It's possible to prove the various versions of L'Hopital's rule using epsilons and deltas. It's really, more or less, a shortcut like all of the derivative and integral formulae.
 
One easy way to think of L'Hopital's rule in its most usual form, is to consider the Taylor series approximations of the two functions:
Suppose a function f(x)\approx{f}(a)+f'(a)(x-a)
in a neighbourhood of x=a. (This is a first-order Taylor-approx.)
Similarly, we have a function g(x)\approx{g}(a)+g'(a)(x-a)
Hence we have that h(x)=\frac{f(x)}{g(x)}\approx\frac{f(a)+f'(a)(x-a)}{g(a)+g'(a)(x-a)}
in the same neighbourhood.
We are interested in \lim_{x\to{a}}h(x)
Furthermore, we assume f(a)=g(a)=0, that is:
h(x)\approx\frac{f'(a)}{g'(a)} close enough.
L'Hopital's rule states that this is, in fact the limit of h(x) as x goes to a.
 
Last edited:
Thank you all of you for your contribution. Finally, I got it.
 

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