What is the Magnetic Field at the Center of a Wire with a Loop?

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SUMMARY

The magnetic field at the center of a circular loop of wire carrying a current can be calculated using the formula \( B = \frac{\mu_{o}I}{2r} \). In this discussion, a current of 4.8 amperes and a loop radius of 7.7 cm were provided. The user initially calculated the magnetic field as 0.0000392 T, which was incorrect. The correct approach requires adding the magnetic field contribution from both the loop and the straight wire segment.

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  • Understanding of Ampère's Law
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  • Knowledge of the permeability of free space (\( \mu_{o} \))
  • Basic algebra for manipulating equations
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Homework Statement



A very long wire carrying a conventional current of 4.8 amperes is straight except for a circular loop of radius 7.7 cm. Calculate the approximate magnitude of the magnetic field at the center of the loop.

I know that I=4.8A and r = .077m
u_o = 4*pi*(10^-7)

Homework Equations


[tex]\mu_{o}I/2r[/tex]


The Attempt at a Solution



I have everything and have been getting .0000392 T for the answer, but it's wrong.

Please help! (ASAP Appreciated...) What am I doing wrong??
 
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You calculated the field due to the loop current correctly. I think you need to add to that the contribution to the magnetic field that comes from the straight part of the wire.
 
Yep, thanks a lot.
 

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