- #1

tnbstudent

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## Homework Statement

A wire circle of radius 0.050 m is embedded in a solenoid of length 0.20 m with 1000 turns that carries a current of 0.50 A. If a vector that is normal to the plane of the circle makes a 40° angle with the axis of the solenoid, what is the magnetic flux through the loop?

## Homework Equations

B (solenoid) = μ*I*n

Flux = B*A*cosθ

## The Attempt at a Solution

n=1000/.2

I'm using the loops per unit length

l=.20m

r=0.05m

I=0.5A

I plugged in the values to solve for the magnetic field:

B=(4*∏*10^-7)*(0.5A)*(1000/.2)

B=0.031T

A=(∏r^2)*(l)

A=1.5e-4 m^3

I'm having some trouble visualizing the angle, but I think the angle should be 50?

Can someone point me in the right direction?