1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

What is the magnetic flux through the prism's right side?

  1. Nov 17, 2014 #1
    1. The problem statement, all variables and given/known data
    e5L8fBt.jpg
    Now, ignore the lengths given in the photo.

    Height (y) = .640 meters
    Length (z) = 1.18 meters
    Base (x) = .320 meters
    Magnetic Field (B) = 3.5 Teslas in the +X direction

    2. Relevant equations
    The problem is to find the magnetic flux through the surface of the prism that is the hypotenuse (side aedf). So, the equation for this should be


    Flux = BAcos(theta)

    3. The attempt at a solution
    Well, working out the problem, I figured out the length of the hypotenuse is 1.22m because of pythagorean theorem. So, B*A is simply

    (1.22)(.640)(3.5T)=2.7328

    Now, theta is the angle that is between the magnetic field and the orthogonal of the surface itself. This angle should be the same as the angle between the base of the triangle and the hypotenuse. So this ratio is (1.18/1.22). So the flux should be

    2.7328 * (1.18/1.22) = 2.6432 Wb

    But the answer keeps spitting out as wrong! What did I do wrong here?
     
    Last edited: Nov 17, 2014
  2. jcsd
  3. Nov 18, 2014 #2
    Perhaps it requires the correct number of significant figures.
    good luck
     
  4. Nov 19, 2014 #3

    rude man

    User Avatar
    Homework Helper
    Gold Member

    I got 0.8164Wb.
    If that checks I can give you hints as to how I derived it.
    Your answer is correct. Guaranteed!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: What is the magnetic flux through the prism's right side?
Loading...