What is the magnitude/direction of the E field?

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In summary, the problem involves a pendulum with a bob of mass 0.005kg and charge of -8.0 uC in a vertical uniform electric field E. Using the equation ∑Fy = qE - mg = ma, we can solve for the magnitude and direction of E by finding an equation for acceleration. The relevant variables are q (charge), E (electric field), m (mass), g (gravity), a (acceleration), L (length), and T (period).
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Vitani11
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Homework Statement


A bob of mass 0.005kg is attached to a pendulum and has a charge of -8.0 uC. The pendulum is 1.0m long and has a periods of 1.2 s when it's puts it in a vertical uniform electric field E. What are the magnitude and direction of E?

Homework Equations


∑Fy = qE - mg = ma

q is charge
E is electric field
m is mass
g is gravity
a is acceleration
L is length
T is period

The Attempt at a Solution


I set up a FBD and this is what I have so far.
 
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  • #2
At this point I'm trying to find an equation for acceleration so I can solve for E.
 
  • #3
Show what you've done.
 

1. What is the magnitude of the E field?

The magnitude of the E field, also known as electric field strength, is a measure of the force per unit charge exerted on a test charge at a specific point in space. It is typically measured in units of newtons per coulomb (N/C) or volts per meter (V/m).

2. How is the magnitude of the E field calculated?

The magnitude of the E field can be calculated using the equation E = F/q, where E is the electric field strength, F is the force exerted on the test charge, and q is the magnitude of the test charge. It can also be calculated using the equation E = kQ/r^2, where k is the Coulomb's constant, Q is the charge of the source, and r is the distance between the source and the test charge.

3. What is the direction of the E field?

The direction of the E field is defined as the direction that a positive test charge would experience a force when placed in the field. It is always directed away from positive charges and towards negative charges. Additionally, the direction of the E field is perpendicular to the equipotential surfaces, which are imaginary surfaces that connect points with the same electric potential.

4. How is the direction of the E field represented?

The direction of the E field is typically represented using electric field lines. These lines are drawn in a way that the tangent to the line at any point gives the direction of the E field at that point. The lines originate from positive charges and terminate on negative charges. The closer the lines are together, the stronger the E field at that point.

5. Can the direction of the E field change?

Yes, the direction of the E field can change depending on the location and orientation of the source charges. It is also affected by the presence of other charges or conductors in the surrounding space. The E field can also change direction as the distance from the source changes. However, the magnitude of the E field remains constant in a vacuum as long as the source charge remains the same.

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