What is the Magnitude of Deceleration of a Meteorite Striking a Car?

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Homework Help Overview

The problem involves a meteorite striking a car, with specific details about the meteorite's weight, the depth of penetration into the trunk, and its initial velocity. The objective is to determine the magnitude of deceleration, assuming it is constant.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate distance, initial and final velocities, and acceleration. There are questions about the meaning of variables in the equations and how to approach the problem without time being explicitly provided.

Discussion Status

The discussion is ongoing, with participants offering various equations and clarifications about the variables involved. Some guidance has been provided regarding the use of kinematic equations that do not require time, but no consensus has been reached on a specific approach.

Contextual Notes

There is a lack of information regarding the time of impact, which is influencing the discussion on how to proceed with the problem. Participants are navigating through the constraints of the problem setup.

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Homework Statement


A 27 lb meteorite struck a car, leaving a 27 cm deep in the trunk. If the meteorite stuck the car with a 520 m/s what was the magnitude of deceleration assuming it to be constant


Homework Equations


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The Attempt at a Solution


I have to be honest I have no clue whatsoever could someone please direct me on how to just attack this question because I have no idea where to begin
 
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Use the simultaneous equations s=vt-\frac{1}{2}at^2 and s=ut+\frac{1}{2}at^2.
 
Sorry if this is a stupid response but I just started taking Physics this week and have no idea what those letters stand for.
 
Well, "s" is the distance, which would be the distance of penetration in this case, "a" is the acceleration, "t" is the time, "v" is the final velocity, and "u" is the initial velocity.
 
So s = 27 cm, a = what your looking for v = 0 m/s u = 520 m/s what's the time here?
 
if you're not given time, you will need to choose a diff eqn or you can plug 1 eqn into another to get rid of time.
 
If you look at your kinematic equations, can you find one that relates all the things you have there without time? You don't need time to solve this problem. You can do it with one equation.
 

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