What is the magnitude of the force on a calcium ion

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SUMMARY

The magnitude of the force on a calcium ion in a cell membrane with an electric field strength of 1.0x10^7 N/C can be calculated using the formula F = Eq. The charge of a calcium ion is +e, where e is approximately 1.6x10^-19 C. Therefore, the correct calculation for the force is F = 1.0x10^7 N/C * 1.6x10^-19 C, resulting in a force of 1.6x10^-12 N. This confirms that the initial assumption of +e being equal to 1 was incorrect.

PREREQUISITES
  • Understanding of electric fields and their effects on charged particles
  • Familiarity with the formula F = Eq for calculating force
  • Knowledge of elementary charge, specifically the value of +e
  • Basic concepts of ion movement in biological membranes
NEXT STEPS
  • Research the implications of electric fields on ion transport in cell membranes
  • Study the role of calcium ions in cellular signaling
  • Learn about the effects of varying electric field strengths on ion movement
  • Explore advanced topics in biophysics related to membrane potential and ion channels
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Students in physics or biophysics, educators teaching cellular biology, and researchers interested in ion transport mechanisms in membranes.

robera1
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Homework Statement


Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.0x10^7 N/C. What is the magnitude of the force on a calcium ion with charge +e?


Homework Equations


E = F/q > F = Eq


The Attempt at a Solution


Well, I thought that +e = ~1, so F = 1.0x10^7(1)
So, F would equal 1.0x10^7, but that is not correct.

Can anyone help me?
 
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What is +e in C? F=Eq is correct.
 
Is +e the same as e-? Because 1 e- is equal to 1.6x10^-19 C, right?
So, is that the same for +e?
 

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