What is the magnitude of the resultant of these two forces?

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SUMMARY

The discussion focuses on calculating the magnitude of the resultant of two forces: 370 N at 11° and 293 N at 34°. The user attempted to resolve the forces into their x and y components using trigonometric functions, resulting in x-components of 606.11 N and y-components of 234.44 N. The correct approach involves using the Pythagorean theorem to find the resultant magnitude, which is derived from the sum of the squares of the x and y components. The suggestion to simplify calculations by choosing one force direction as the x-axis is also highlighted.

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  • Familiarity with the Pythagorean theorem
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Homework Statement



Two forces, 370 N at 11◦ and 293 N at 34◦ are
applied to a car in an effort to accelerate it.

3765 kg
370 N
11◦
293 N
34◦

What is the magnitude of the resultant of
these two forces?
Answer in units of N



Homework Equations





The Attempt at a Solution


I've tried find both xs of the forces using 370cos11=363.20 and 293cos34=242.91 adding them together to get 606.11, then I found the two ys using 370sin11=70.60 and 293sin34=163.84 adding them together to get 234.44. I then added the x^2 and y^2 of the two sums and square rooted them. What am I doing wrong?
 
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Welcome to PF!

Hi hammerbox! Welcome to PF! :smile:

(have a degree: º and try using the X2 tag just above the Reply box :wink:)
hammerbox said:
Two forces, 370 N at 11◦ and 293 N at 34◦ are
applied to a car in an effort to accelerate it.

3765 kg
370 N
11◦
293 N
34◦

What is the magnitude of the resultant of
these two forces?
Answer in units of N

I've tried find both xs of the forces using 370cos11=363.20 and 293cos34=242.91 adding them together to get 606.11, then I found the two ys using 370sin11=70.60 and 293sin34=163.84 adding them together to get 234.44. I then added the x^2 and y^2 of the two sums and square rooted them. What am I doing wrong?

Looks ok to me. :smile:

(btw, you could save a little time by using one of the force directions as your x direction … then you only have to look up cos23º and sin23º :wink:)
 

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