(adsbygoogle = window.adsbygoogle || []).push({}); Another Magnitude and Direction of resultant force ???

I'm having issues on the second question. I feel that I'm missing some information. Since the lines are perpendicular do I consider one force (10N) at 90 degrees North? And if this is the case then is the other force (15N) at __ degrees East and solve with the second equation below?

1. The problem statement, all variables and given/known data

A - Consider two forces, one having a magnitude of 10N, and the other having a magnitude of 15N. What maximum net force is possible when combining these two forces? What is the minimum net force possible?GOT THIS PART

B - If the forces given in a) above are perpendicular to each other, what will be the magnitude and direction of the resultant force?Given by prof ...requires vector addition.

2. Relevant equations

R = sqrt(A^2 + B^2)

Ax = cosA, Ay = sinA

tan = y/x

3. The attempt at a solution

Max Net Force

10 N + 15 N = 25 N

Min Net Force

10 N - 15 N = -5 N

Resultant Force of perpendicular lines

[tex]\sqrt{10^2 + 15^2}[/tex]

[tex]\sqrt{325}[/tex] = 18.02775... Magnitude ??? Direction would possibly be 18 degrees of North or East???

This is where I get stuck....help??

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# Homework Help: Another Magnitude and Direction of resultant force ?

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