What is the magnitude of the vector sum of the four vectors

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SUMMARY

The magnitude of the vector sum of four vectors, each with a magnitude of 62 m, arranged in a parallelogram configuration, is determined by the angles between them. Specifically, the angle between vectors A and B is 49 degrees, which implies that the angle between vectors C and D is also 49 degrees, while the angles between A and C and between B and D are 131 degrees. To find the resultant vector, one must consider the additive nature of the vectors based on their orientations. The diagonal of the parallelogram formed by these vectors represents the magnitude of their vector sum.

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Four vectors, each of magnitude 62 m, lie along the sides of a parallelogram as shown in the figure. The angle between vector A and B is 49 degrees.
What is the magnitude of the vector sum of the four vectors? Answer in units of m.

So far, I have drawn the picture and made out with a parallelogram with the left side as vector A, the top vector C, the right vector D, and the bottom vector B with all of the sides congruent to each other respective to 62 m, and also the angle with between vector A and B is 49 degrees which also means that between C and D is the same while between both A and C and B and D is 131 degrees in between.

What I've been thinking was since I have to find the magnitude of the vector sum of the four vectors, wouldn't it be the same as finding the magnitude diagonal of the parallelogram? or am I off the tee here?
 
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Can you post a link to the figure, or uplink it as an attachment? We'd like to help, but we need the figure. Thanks.
 
If A and C point in the same direction (parallel), they are additive, otherwise if anti-parallel they cancel. Similarly for B and D.

If the head (point) of A touches the tail of B, then they are additive, and resultant is the diagonal. If the point of B touches the tail of C, then C is in the opposite direction of A, and their contributions to the vector sum cancel.
 

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