What is the maximum amplitude of oscillation of the system

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Homework Help Overview

The problem involves a block executing simple harmonic motion on a frictionless surface, with another block resting on it. The objective is to determine the maximum amplitude of oscillation to prevent slipping, given the frequency and coefficient of static friction.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for maximum acceleration in simple harmonic motion and its application to the problem. There is also a question regarding the correct form of the acceleration equation, with some participants clarifying the significance of the negative sign in the context of vector direction.

Discussion Status

Some participants express agreement with the original poster's approach, while others seek clarification on the acceleration formula. The discussion reflects a mix of validation and inquiry into the underlying concepts.

Contextual Notes

Participants are navigating the implications of static friction and the conditions under which block B remains stationary relative to block P. There is an emphasis on understanding the relationship between amplitude, frequency, and acceleration without reaching a definitive conclusion.

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Homework Statement


A large block P executes horizontal simple harmonic motion as it slides across a frictionless surface with a frequency f = 1.5 Hz. Block B rests on it, as shown in the figure, and the coefficient of static friction between the two is 0.6. What is the maximum amplitude of oscillation of the system so that block B dos not slip?


Homework Equations


[tex]a=-\omega ^2*A[/tex]

[tex]\omega = 2\pi f[/tex]


The Attempt at a Solution



[tex]a=\omega ^2*A[/tex]

[tex]\frac{F}{m}=(2\pi f)^2*A[/tex]

[tex]A=\frac{\mu _s*N}{m*(2\pi f)^2}[/tex]

[tex]A=\frac{\mu _s*mg}{m*(2\pi f)^2}[/tex]

[tex]A=6.62~cm[/tex]

Do I get it right?

Thanks
 
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It looks good to me!
I haven't seen that acceleration formula before, so I'm no expert on this.
 


Hi Delphi51

It's formula for maximum acceleration of simple harmonic motion. Thanks a lot for your reply.
 


a = - w^2 * A or a = w^2 *A??

which is right??
 


SAT2400 said:
a = - w^2 * A or a = w^2 *A??

which is right??

[tex]a=-\omega ^2 A[/tex] is right because acceleration is vector. The negative sign indicates that the direction of the acceleration is in the opposite direction of the direction of motion of the particle.

In my case, I just need the numerical value so I omit the negative sign
 

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