What is the maximum B-field in the iron core?

Click For Summary
SUMMARY

The maximum magnetic field (B-field) in the iron core of a transformer can be calculated using the formula for electromotive force (EMF) and the relationship between magnetic flux and area. Given a secondary coil with a turns ratio of 6:1, a secondary voltage of 10V (rms), and a cross-sectional area of 4 cm², the maximum B-field can be derived from the equation \(\frac{\Delta (B \cdot A)}{\Delta t} = E\). The greatest rate of change in B is determined to be \(2 \pi f \times B_{max}\), emphasizing the necessity of differentiation in solving this problem.

PREREQUISITES
  • Understanding of transformer principles and turns ratio
  • Familiarity with electromotive force (EMF) equations
  • Basic knowledge of magnetic fields and flux
  • Proficiency in calculus, particularly differentiation
NEXT STEPS
  • Study transformer equations and their applications in electrical engineering
  • Learn about the relationship between voltage, frequency, and magnetic fields in AC circuits
  • Explore the principles of differentiation in the context of electromagnetic theory
  • Investigate the effects of core material on magnetic field strength and transformer efficiency
USEFUL FOR

Electrical engineering students, physics enthusiasts, and professionals involved in transformer design and analysis will benefit from this discussion.

Clari
Messages
62
Reaction score
0
A student wishes to light a lamp rated 12V, yet he has only a 2V rms a.c supply with variable frequency. So he attempts to step up the voltage by means of a transformer. Given Ns:Np = 6:1, resistance in the primary circuit is 70 ohm, inductance of primary coil is 0.3H, frequency f is 50Hz

a.) If Ns = 600, Vs = 10V (rms), cross-sectional area of the secondary coil is 2cmx2cm, what is the maximum B-field in the iron core?

i find this question really difficult, because my teacher uses differentiation to solve it...:confused: i wonder if there are simple ways to solve it. Thanks!
 
Physics news on Phys.org
[tex]\frac{\Delta (B \cdot A)}{\Delta t} = E \cdot circumference[/tex] .

in 1/200 sec (that is, .005 s), B changes from zero to its maximum.
You might expect that the greatest rate of change in B is 200/s times B_max ;
but in fact, the greatest rate of change in B is (2 pi f) times B_max .
(recall velocity of an oscillator?)
This is why you really need to take derivitives.
 

Similar threads

  • · Replies 43 ·
2
Replies
43
Views
8K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K