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What is the maximum mass that can be hung from the end of a boom?

  1. Nov 12, 2009 #1
    1. The problem statement, all variables and given/known data
    In the figure, a boom of mass 1000kg is supporting a mass m. The base has a mass of 10,000kg. (a) What is the maximum mass m that can be hung from the end of the boom? (b) If this amount of mass is haning off the boom, where is the center of gravity of the entire system relative to C.G. (base)? (c) What is the corresponding tension in the cable assuming the cable makes an angle of 46.5 degrees relative to the horizontal? (d) What is the strain in the boom's pin (support)?


    2. Relevant equations

    Torque net=0
    Force net=0
    Weight=mg

    3. The attempt at a solution

    Weight of boom=(1000kg)(9.80m/s2)=9800N
    Torque net=0
    0=-W(boom)rsin(theta)-W(mass)rsin(theta)+Tensionrsin(theta)
    0=(9800N)(10m)sin(theta)-m(9.80m/s2)rsin(theta)+Trsin(theta)

    I don't know what values to use for my angles, but there would still be too many unknowns. so i think that i'm setting up my equation completely wrong, but can't think of anything else to do. once i find the mass then i think i know how to do the other parts of the question.
     

    Attached Files:

  2. jcsd
  3. Nov 12, 2009 #2

    tiny-tim

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    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi a.wright! Welcome to PF! :smile:

    (have a theta: θ :wink:)
    I don't understand your torque equation …

    about which point are you taking torques?

    and why does the tension come into it? :confused:

    Perhaps you're missing the point … if the mass is too heavy, the whole system will overbalance, and your torque equation should be determining when that happens. :wink:
     
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