What Is the Maximum Speed a Car Can Turn Without Skidding?

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SUMMARY

The maximum speed a car can turn without skidding on an unbanked road is determined by the relationship between centripetal acceleration and static friction. Given a minimum turning radius of 8.2 m and a coefficient of static friction (µ) of 0.2, the centripetal acceleration (a_c) must equal the force of static friction. By equating these forces, the necessary calculations reveal the maximum safe speed for turning without skidding.

PREREQUISITES
  • Understanding of centripetal acceleration (a_c = V^2/R)
  • Knowledge of static friction (F ≤ µN)
  • Familiarity with the concept of normal force (N = mg)
  • Basic geometry of circles (Circumference C = 2πr)
NEXT STEPS
  • Calculate maximum speed using the formula V = √(µgR)
  • Explore the effects of different coefficients of friction on vehicle dynamics
  • Investigate the impact of banking angles on turning speed
  • Learn about vehicle stability and dynamics in various road conditions
USEFUL FOR

Automotive engineers, physics students, and anyone interested in vehicle dynamics and safety during turns.

Trentonx
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A certain car has a minimum turning radius of 8.2 m. If the coefficient of static friction between the tires and road is µ = 0.2, what is the maximum speed the car can have without skidding on an unbanked road if the steering wheel is turned fully to the right?

I know that this problem will need that centripetal acceleration is equal to velocity squared over the radius. a_c=V^2/R
Also, F≤μN, the equation of static friction.
Possibly the Circumference of a circle C=2(pi)r

I am assuming that the a_c has to be equal to the static friction. However, the only problems with static friction have been blocks sitting on level surfaces and inclines. I know that a_c points towards the center of the circle, but which way does the friction force go?
 
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Welcome to PF.

You've got the general idea.

just equate the 2 forces - friction and centripetal - the masses drop out and you have the condition you need to satisfy.
 
I hadn't even thought of the fact the the normal force is just mg. Thanks, that was the help I needed.
 

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