What is the meaning of relative motion equation in a rigid body?

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The discussion centers on the concept of relative motion in rigid bodies, specifically addressing the equation V(b1) = V(A) as presented in a textbook. It clarifies that the velocity of point B relative to point A (V(B/A)) must be perpendicular to the line segment AB, due to the constancy of the distance between points A and B. The participants emphasize that this relationship is defined by the rigid body's motion, which is purely rotational without translational components along the line AB.

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Hi I have learned Dynamics in school;;;

I have problem in relative motion chapter[rigid body & fixed position]

upload some picture.

PB170008.JPG


PB170009.JPG


first picture is my textbook page. In picture. textbook says to me that V(b1)=V(A)

because this particle is rigid body and point doesn't change their position each other on surface. So their moving is just rotating.

and second picture say that meaning of relative motion equation in rigid body.

My question :::::

why did't textbook say V(A)=V(b1)+some element heading to V(b2) ?

In my think it is possible V(A) has some element about b(2) axis (first picture)

but in my textbook V(A) has only b(1) direction. It make me crazy.

help me~~~~~~~~``
 
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hi g460cbk! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)

VB/A (the velocity of B relative to A) must be perpendicular to AB

this is because AB2 is constant, ie AB.AB = constant, so AB.d(AB)/dt = 0, ie AB.VB/A = 0

AB lies entirely along b1 (this is how unit vector b1 is defined), so VB/A lies entirely along b2 :wink:
 


thank you for your help

I never know (d/dt)AB^2=0 .

you're genious!
 

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