MHB What is the Minimal Area of a Right-Angled Triangle with an Inradius of 1 Unit?

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What is the minimal area of a right-angled triangle whose inradius is 1 unit?
 
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The area of a triangle is \(A = sr\), where \(r\) is the inradius (\(r=1\)) and \(s = (a + b + c)/2\) is the semiperimeter. Apparently, the smallest area is obtained when the semiperimeter - or perimeter - is smallest. This happens, when the triangle is isosceles. The right isosceles triangle with incircle radius 1 has side length $$a = (1 + \sqrt{2})\sqrt{2} = 2 + \sqrt{2}.$$ The area of it is $$A = a^2/2 = 2 + \sqrt{2} + 1 = 3 + \sqrt{2}.$$
 
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I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

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