What Is the Minimal Velocity for an Arrow to Pass Through a Rotating Wheel?

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Homework Help Overview

The problem involves a rotating wheel with six spokes and an arrow that needs to pass through it without touching the spokes. The wheel's angular velocity and the dimensions of both the wheel and the arrow are provided, leading to a question about the minimal velocity required for the arrow.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the angular velocity of the wheel and the linear velocity required for the arrow, with some questioning the correctness of unit conversions and the implications of the arrow's length relative to the wheel's radius.

Discussion Status

Several participants have provided feedback on the original poster's calculations, particularly regarding unit consistency. There is an acknowledgment of the need to ensure that the speed is expressed correctly, and some suggest that the arrow could be thrown gently due to its length being less than the radius of the wheel.

Contextual Notes

There is a mention of potential unit conversion issues, as well as the original poster's approach to calculating the velocity based on the time it takes for a spoke to rotate. The discussion reflects a mix of interpretations regarding the necessary conditions for the arrow to pass through the wheel.

Dansuer
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Homework Statement


A wheel has six spokes of length 30 cm. The wheel is rotating with an angular velocity of 2.5 rotation per second. We want to throw an arrow, of length 24 cm, through the wheel. What is the minimal velocity required for the arrow to go through the wheel without touching the spokes.

Homework Equations



v = s / t

\omega = \theta / t

The Attempt at a Solution



The times for the arrow to go through have to be equal the time one spoke goes around 1/6 of the wheel.

so the system: v = s/t and \omega = \theta / t

gives: v = (\omega / \theta) * s

\omega = 2.5 rotation per second * 360degree = 900 degree/s

\theta = 360 degree / 6 = 60 degree

v = (\omega / \theta) * s = (900 degree/s / 60 degree) * 24 cm = 360 cm

is this right?
 
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first, speed is not in cm.

second, convert 24 cm into m

rest is perfectly correct
 
Hi Dansuer! :smile:

(have a theta: θ and an omega: ω :wink:)

Yes, that looks fine, except for the units …

your speed should be 360 cm/s, not 360 cm, shouldn't it? :wink:

(since the question is entirely in cm, I suspect it may not be necessary to convert to m/s)

However, since the arrow is shorter than the radius, you can just throw the arrow gently sideways! :smile:
 
thanks a lot for your answers !
 

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