What Is the Minimum Amount of Money Needed with Different Coin Combinations?

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SUMMARY

The discussion focuses on determining the minimum amount of money required using combinations of cents, nickels, dimes, and quarters with specific constraints on the number of coins. For four coins, the minimum is 4 cents (four 1-cent coins). For five coins, the minimum is 9 cents (one nickel and four 1-cent coins). For six coins, the minimum is 19 cents (one nickel, one dime, and four 1-cent coins). The participants highlight the importance of combinatorial methods to explore further combinations for seven and eight coins.

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  • Basic arithmetic operations
  • Ability to partition sets
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  • Study coin problem variations and their solutions
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Homework Statement



use combinatorial methods to determine the smallest amount of money that using cents, nickels, dimes, or quarters, requires
a) four coins
b) five coins
c) six coins
d) seven coins
e) eight coins

Hint: Consider the ways to partition sets of those respective sizes and calculate their minimum values.

Homework Equations





The Attempt at a Solution



a) four coins => 4 cents (1cent+1cent+1cent+1cent)

b) five coins => 9 cents (1nickel + 4 cents)

c) six coins => 19 cents (1 nickel + 1 dime + 4 cents)

I don't know how to do d) ans e)

I can't use 5 cents , because this is makes 1 nickel.

Please help. Thank you.
 
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mamma_mia66 said:
I can't use 5 cents , because this is makes 1 nickel.

By similar reasoning:
You can't use 2 nickels because they make 1 dime.
You can't use 2 dimes and 1 nickel because they make 1 quarter.
These restrictions help you pick the next coin, but the question requires the use of combinatorial methods.
 

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