What Is the Minimum and Maximum Acceleration for a Block on an Inclined Wedge?

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SUMMARY

The discussion focuses on determining the minimum and maximum horizontal acceleration (a) for a block resting on an inclined wedge at angle θ, with a coefficient of friction μ. The derived formula for the minimum acceleration is a = g(sin(θ) + μ cos(θ)) / (cos(θ) - μ sin(θ)), which indicates that the block will remain stationary on the wedge without sliding if this condition is met. The analysis reveals that the limiting values for acceleration are not a range but a specific value, emphasizing the importance of static friction in maintaining equilibrium.

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  • Understanding of Newton's laws of motion
  • Familiarity with static friction concepts
  • Knowledge of trigonometric functions related to angles
  • Basic algebra for manipulating equations
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  • Study the derivation of forces acting on inclined planes
  • Learn about static and kinetic friction coefficients
  • Explore applications of Newton's laws in non-inertial reference frames
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Homework Statement



A block rests on a wedge inclined at an angle \theta. The coefficient of friction between the block and the plane is \mu.Let the wedge move with horizontal acceleration a to the right. Assuming
that tan tan(\theta) < \mu, find the minimum value of a for the block to remain on the wedge without sliding.

Also find the maximum value of a.

Homework Equations



The Attempt at a Solution



mgcos(\theta)+masin(\theta)=F_{normal};<br /> \tex{mgcos(\theta)+\mu (F_{normal})=macos(\theta);<br /> <br /> a=\frac{g(sin+\mu cos}{cos - \mu sin}

which gives wacky limiting values and isn't a range at all but just one value.
 
Last edited:
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Have a bit correction with this one: F_{static friction} \leq \mu F_{normal}
Also, there must be a condition for a to be positive, as a acts to the right.
 

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