What Is the Minimum Force Required to Move the Box?

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SUMMARY

The minimum horizontal force required to move an 8 kg box, which has a coefficient of static friction 1.21 times greater than its kinetic friction, can be calculated using the principles of friction. The box initially travels at 11 m/s and comes to rest after 46 meters due to kinetic friction. To find the necessary force to overcome static friction, one must first determine the kinetic friction force that stopped the box, then calculate the static friction force using the relationship between the coefficients of friction.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of friction coefficients (static and kinetic)
  • Ability to calculate forces using basic physics equations
  • Familiarity with free body diagrams
NEXT STEPS
  • Calculate the kinetic friction force using the formula: F_friction = μ_k * F_n
  • Determine the coefficient of kinetic friction (μ_k) from the given data
  • Calculate the coefficient of static friction (μ_s) using the relationship μ_s = 1.21 * μ_k
  • Use the static friction coefficient to find the minimum force needed to move the box again
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and friction, as well as anyone needing to solve problems related to forces and motion in a practical context.

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Homework Statement


A 8 kg box is initially traveling on a horizontal surface at a speed of 11 m/s and comes to rest after 46 meters due to the force of friction. If the coefficient of static friction is 1.21 times more than the coefficient of the kinetic friction, what is the minimum horizontal force needed in Newtons in order to move the box again?


Homework Equations


i drew out all my forces but not sure where to go from here


The Attempt at a Solution


All i found so fare was the Fn=78.48
 
Last edited:
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flsurfer said:

Homework Statement


A 8 kg box is initially traveling on a horizontal surface at a speed of 11 m/s and comes to rest after 46 meters due to the force of friction. If the coefficient of static friction is 1.21 times more than the coefficient of the kinetic friction, what is the minimum horizontal force needed in Newtons in order to move the box again?


Homework Equations


i drew out all my forces but not sure where to go from here


The Attempt at a Solution


Welcome to PF.

You need to first determine the force that the kinetic friction induced to slow it down.

Knowing that, you can determine the u of kinetic friction and then to figure the u of static friction that you can use to figure the force that needs to be overcome again.
 

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