What is the minimum frequency to keep the mass moving?

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SUMMARY

The minimum frequency required to keep a mass of 200 grams tied to a 1.6-meter string moving in a vertical circle is determined using the equation Fc = m4(pi)^2rf^2, where Fc represents the centripetal force. The gravitational force (Fg) acting on the mass must be considered, particularly at the top of the circle where it aids in maintaining motion. At the bottom of the circle, the centripetal force must overcome gravity. This understanding clarifies the relationship between gravitational force and centripetal force in circular motion.

PREREQUISITES
  • Understanding of centripetal force and gravitational force
  • Familiarity with the equation Fc = m4(pi)^2rf^2
  • Basic knowledge of circular motion dynamics
  • Ability to draw and interpret diagrams of forces in motion
NEXT STEPS
  • Study the derivation of the centripetal force equation in circular motion
  • Learn how to apply Newton's laws to circular motion problems
  • Explore the effects of varying mass and radius on frequency in circular motion
  • Investigate real-world applications of centripetal force in engineering
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to forces in motion.

Smartgurl
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Homework Statement


A mass of 2.0 x 10^2 g is tied to a 1.6 m long string and spun in a vertical circle. What is the minimum frequency to keep the mass moving?

Homework Equations


Fc=m4(pie)rf^2

The Attempt at a Solution


I know I have to use this equation and make it equal to another to find Fc however I don't know which other equation.
 
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Well, perhaps this isn't done in outer space but on earth...
 
Smartgurl said:
Fc=m4(pie)rf^2
That equation is not quite right. (And it's spelt pi, not pie.)
 
haruspex said:
That equation is not quite right. (And it's spelt pi, not pie.)
Is the equation Fc = m4(pi)^2rf^2
 
Smartgurl said:
Is the equation Fc = m4(pi)^2rf^2
Yes.
Now what about BvU's point? You need to consider gravity.
 
haruspex said:
Yes.
Now what about BvU's point? You need to consider gravity.
Would Fg = Fc?
So I could get mg = m4(pi)^2rf^2. Then solve for f?
 
Smartgurl said:
Would Fg = Fc?
So I could get mg = m4(pi)^2rf^2. Then solve for f?
Yes, but is that just a lucky guess or can you mount an argument to say it should be that?
 
haruspex said:
Yes, but is that just a lucky guess or can you mount an argument to say it should be that?
I drew a diagram and I think that when the mass is at the top it will need the minimum Fc as gravity will help bring it down. Where at the bottom the Fc will have to overcome gravity to bring the mass back up. So gravity will be the only force acting on the mass and bringing it down when it is at the top.
 
Smartgurl said:
I drew a diagram and I think that when the mass is at the top it will need the minimum Fc as gravity will help bring it down. Where at the bottom the Fc will have to overcome gravity to bring the mass back up. So gravity will be the only force acting on the mass and bringing it down when it is at the top.
Good.
 
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haruspex said:
Good.
Thank you so much! Now it seems simple since I understand it
 

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