What is the Minimum Height for Anchoring the Cable to the Wall?

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SUMMARY

The discussion centers on calculating the minimum height for anchoring a cable to a wall that supports a sign and a uniform rod. The sign weighs 66 kg, and the rod has a mass of 8.2 kg with a length of 2.3 m. The maximum tension the cable can withstand is 800 N. The total force acting on the system is calculated as 727.16 N, and the torque generated by this force is 1672.5 N·m. The key to solving the problem lies in determining the torque created by the tension in the cable.

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Homework Statement


A 66 kg sign hung centered from a uniform rod of mass 8.2kg and length 2.3m. At one end the rod is attached to the wall by a pivot; at the other end it's supported by a cable that can withstand a maximum tension of 800 N. what is the minimum height h above the pivot for anchoring the cable to the wall?



Homework Equations



Not entirely sure if these apply.

[tex]\tau[/tex] = r x F
[tex]\tau[/tex] = [tex]\Sigma[/tex]

The Attempt at a Solution



Mg = (74.2)(9.8) = 727.16 N (Total Fy)

[tex]\tau[/tex] = (2.3)*(727.16) = 1672.5

After I get this information I'm lost.
 
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Hi SpeedPhysics ! Welcome to PF! :smile:
SpeedPhysics said:
A 66 kg sign hung centered from a uniform rod of mass 8.2kg and length 2.3m. At one end the rod is attached to the wall by a pivot; at the other end it's supported by a cable that can withstand a maximum tension of 800 N. what is the minimum height h above the pivot for anchoring the cable to the wall?

Mg = (74.2)(9.8) = 727.16 N (Total Fy)

[tex]\tau[/tex] = (2.3)*(727.16) = 1672.5

(it's not 2.3 … the weight goes through the centre :wink:)

ok, that's the torque (the moment) of the weight …

now, if you call the tension T, what's the torque of the tension? :smile:
 

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