The problem involves calculating the minimum work required to operate a Carnot refrigerator that extracts heat from an object at 0°C and rejects it to a hot reservoir at 19°C. The specific heat extracted is 433J.
Multiple attempts to calculate the work have been presented, with some participants providing reasoning for their calculations. There is an ongoing exploration of the relationships between COP, heat extracted, and work done, but no consensus has been reached on a single method or final answer.
Participants are working under the constraints of using the Carnot efficiency and the specific temperatures provided, while also noting the need for clarity in reasoning behind their calculations.
COP = Qc/W. So express W in terms of COP and Qc and solve.Runaway said:Homework Statement
433J of heat is extracted from a massive object at 0[tex]\circ[/tex]C while rejecting heat to a hot reservoir at 19[tex]\circ[/tex]C.
What minimum amount of work will accomplish this? Answer in units of J.
Homework Equations
COP= Qc/(Qh-Qc) = Tc/(Th-Tc)
The Attempt at a Solution
433J * 273.15K/(292.15K-273.15K)=6224.944 joules
Yes. But you should explain your reasoning.Runaway said:W= 433j/(273.15k/(292.15k-273.15k)) = 30.119j?