What Is the Modulus of z When z=(x-iy)/(x+iy)?

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SUMMARY

The modulus of the complex number z, defined as z=(x-iy)/(x+iy), is confirmed to be 1. The solution involves separating the expression into real and imaginary parts, ultimately utilizing the property |z_1/z_2| = |z_1|/|z_2| to simplify the calculation. This method provides a straightforward approach to determine the modulus without extensive manipulation of the equation.

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alijan kk
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Homework Statement


if z=(x-iy)/(x+iy) then modulus of z is :

Homework Equations

The Attempt at a Solution


(x-iy)/(x+iy)= (x2-y2-2x(iy))/(x2+y2)

i can't get the real part and the imaginary part to take the modulus :

but the answer in any way could be = 1 ?

the answer in the book is 1 .
 
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alijan kk said:
(x-iy)/(x+iy)= (x2-y2-2x(iy))/(x2+y2)

i can't get the real part and the imaginary part to take the modulus :
But you have it there. Simply split what you have on the right-hand side into real and imaginary parts.
 
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DrClaude said:
But you have it there. Simply split what you have on the right-hand side into real and imaginary parts.
i got one the answer,
thank you so much :)
 
It is easier to use that ## |z_1/z_2| = |z_1|/|z_2|##
 
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ehild said:
It is easier to use that ## |z_1/z_2| = |z_1|/|z_2|##
thanks a lot, it was actually a multiple choice question, and you gave me a quicker way
 

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