What is the molar heat of combustion for ethanol?

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SUMMARY

The molar heat of combustion for ethanol can be calculated using the formula: heat evolved per gram divided by the molar mass of ethanol. In this discussion, 2.9 grams of ethanol releases 87 kJ of heat. The molar mass of ethanol is 46 g/mol, leading to the calculation of moles as 2.9 g / 46 g/mol. Consequently, the molar heat of combustion is determined to be 87 kJ divided by the number of moles calculated from 2.9 grams.

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bada man
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The question i am stuck on is "If 2.9g of ethanol burn with the evolution of 87 kj of heat, what is the molar heat of combustion of ethanol?" thank you for your help if it possible you can tell me how to do this question.
 
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2.9g ethanol - how many moles?
 
so basically so find how many moles of ethanol in 2.9g

So u do, 2.9g/46 (46 being the molar mass of ethanol)
 
87 kJ for 2.9/46 moles, how much for 1 mole?
 

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