What is the moment of inertia of the plate about z axis?

Click For Summary
SUMMARY

The moment of inertia of an isosceles triangular plate about the z-axis is calculated using the parallel axes theorem and integration techniques. The mass of the triangle is denoted as M, and the base length is L. The moment of inertia is derived as Ml²/12 through integration of the form ∫(x² + y²)dm, confirming that the moment of inertia for the triangle is not simply half that of a square. The discussion emphasizes the importance of understanding the geometry of the shape and the distribution of mass in calculating the moment of inertia.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with the parallel axes theorem
  • Basic knowledge of integration techniques in physics
  • Ability to analyze geometric shapes and their properties
NEXT STEPS
  • Study the parallel axes theorem in detail
  • Learn integration techniques for calculating moments of inertia
  • Explore the moment of inertia for various geometric shapes
  • Investigate applications of moment of inertia in engineering and physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, engineers involved in structural analysis, and anyone interested in the properties of materials and their rotational dynamics.

zorro
Messages
1,378
Reaction score
0

Homework Statement



What is the moment of inertia of the plate about z axis?


Homework Equations





The Attempt at a Solution



Consider the isosceles triangle to be a part of a square of side l/root(2)
Its mass will be 2M
We know that its moment of inertia about the centre perpendicular to the plane is 2M(l^2/2)/6=Ml^2/6
Applying parallel axes theorem, moment of inertia about z axis will be Ml^2/6 + 2M(l^2/4)
which is 2/3 (Ml^2)
Moment of inertia of the triangle will be half of it i.e. Ml^2/3
but the answer is Ml^2/6
Please explain if there is any other easier approach.
So the moment of inertia of the triangle will be half of it i.e. Ml^2/12
 

Attachments

  • I.jpg
    I.jpg
    2.1 KB · Views: 766
Physics news on Phys.org
What is the moment of inertia of the plate about z axis?

What is the shape of the plate and the point of suspension?
 
I am sorry I did not post the full question. Here it is.

The figure shows an isosceles triangular plate of mass M and base L. The angle at the apex is 90°. The apex lies at the origin and the base is parallel to X-axis
 
The moment of inertia of the triangle is not half that of the square. See the picture: the points of the upper triangle are farther than those of the lower triangle.

It is easy to get the moment of inertia by integrating (x^2+y^2)dm for the triangle.

ehild
 

Attachments

  • momentinertia.JPG
    momentinertia.JPG
    3.5 KB · Views: 711
The base of the triangle is fixed ( it is of length l). Since the apex angle is 90 degrees and it is isosceles, You get a square when it is rotated about l. So there is no chance of upper triangle being bigger or smaller.
 
How is the moment of inertia defined for an extended body?

ehild
 
here the extended body is a square. So its moment of inertia is same as that of a square.
 
You did not understand me. Forget for the moment that this triangle is half of a square. It is just a set of elementary masses, organized in a certain shape. How would you get the moment of inertia of a set of point masses?

ehild
 
By using the equation ∫x^2 dm
 
  • #10
What do you mean on x? If x is the horizontal axis, a rod along the y-axis has zero moment of inertia?



ehild
 

Similar threads

Replies
2
Views
2K
  • · Replies 28 ·
Replies
28
Views
2K
Replies
25
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
8
Views
2K
Replies
52
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K