alextrainer Messages 10 Reaction score 0 Thread starter Jan 26, 2017 #1 Not sure how to use a single area and line segments that are same to calculate the areas and line segments for the areas. Attachments geo prob stacked.jpg 5.1 KB · Views: 144
Not sure how to use a single area and line segments that are same to calculate the areas and line segments for the areas.
Greg Gold Member MHB Messages 1,377 Reaction score 0 Jan 27, 2017 #2 Using the formula for the area, $A$, of a triangle $$A=\frac{bh}{2}$$ where $b$ is the base of the triangle and $h$ is the height of the triangle, can you state the area of triangle $CDE$ in terms of $AG$ and $DG$?
Using the formula for the area, $A$, of a triangle $$A=\frac{bh}{2}$$ where $b$ is the base of the triangle and $h$ is the height of the triangle, can you state the area of triangle $CDE$ in terms of $AG$ and $DG$?
Greg Gold Member MHB Messages 1,377 Reaction score 0 Jan 27, 2017 #4 $$\frac{\frac13AG\cdot\frac13DG}{2}=42$$ Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$?
$$\frac{\frac13AG\cdot\frac13DG}{2}=42$$ Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$?
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Jan 27, 2017 #5 greg1313 said: $$\frac{\frac13AG\cdot\frac13DG}{2}=42$$ Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$? Greg, I'm glad you can read that tiny sideways image, because I sure can't. (Bandit)
greg1313 said: $$\frac{\frac13AG\cdot\frac13DG}{2}=42$$ Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$? Greg, I'm glad you can read that tiny sideways image, because I sure can't. (Bandit)