- #1

1irishman

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## Homework Statement

A force of 2N east and a force of 3N 25degrees N of E act on an object. What is the net force on the object?

The answer according to the text is 4.9N 75Degrees E of N

## Homework Equations

## The Attempt at a Solution

First express direction in terms of x-axis:

Resolve 2N East into x and y components

Rx = R cos Theta Ry = R sin Theta

=2Ncos180 =2Nsin180

= -1.9N =0

Resolve 3N 25degrees N of E into x and y components

Rx = R cos Theta Ry = R sin Theta

=3cos335degrees =3sin335degrees

=1.6N = -2.6N

Add x components

Rx=R1x+R2x

= -1.9N + 1.6N

= -0.3N west direction because of minus sign

Add y components

Ry=R1y+R2y

=0N + -2.6N

= -2.6N south direction because of minus sign

Add Rx and Ry to obtain R

R= sqrt Rx^2 + Ry^2

= -0.3^2 + -2.6^2

= sqrt of 6.85

= 2.62N

arc tan -0.3/-2.6= theta

I don't understand how the answer is what they got? Please help?