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1irishman
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Homework Statement
A force of 2N east and a force of 3N 25degrees N of E act on an object. What is the net force on the object?
The answer according to the text is 4.9N 75Degrees E of N
Homework Equations
The Attempt at a Solution
First express direction in terms of x-axis:
Resolve 2N East into x and y components
Rx = R cos Theta Ry = R sin Theta
=2Ncos180 =2Nsin180
= -1.9N =0
Resolve 3N 25degrees N of E into x and y components
Rx = R cos Theta Ry = R sin Theta
=3cos335degrees =3sin335degrees
=1.6N = -2.6N
Add x components
Rx=R1x+R2x
= -1.9N + 1.6N
= -0.3N west direction because of minus sign
Add y components
Ry=R1y+R2y
=0N + -2.6N
= -2.6N south direction because of minus sign
Add Rx and Ry to obtain R
R= sqrt Rx^2 + Ry^2
= -0.3^2 + -2.6^2
= sqrt of 6.85
= 2.62N
arc tan -0.3/-2.6= theta
I don't understand how the answer is what they got? Please help?