What is the normal force between two stacked boxes?

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The normal force exerted by the 19.0-kg box on the 10.0-kg box is equal to the weight of the 10.0-kg box, which is 98.1 N (10 kg * 9.81 m/s^2). If the normal force exceeds this value, the 10.0-kg box would accelerate upward, indicating an unbalanced force. To solve these problems effectively, free body diagrams should be drawn to visualize the forces acting on each box. The normal force on the 19.0-kg box must also account for the weight of the 10.0-kg box above it. Understanding these principles is crucial for analyzing the forces in stacked box scenarios.
tristanmagnum
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A 10.0-kg box is placed on top of the 19.0-kg box, as shown in the figure. Determine the normal force that the 19.0-kg box exerts on the 10.0-kg box.

i know what the normal force of the 19 kg box. i am having problem setting these kind of problems.
 
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What happens to the 10 kg box if the normal force is greater than 10 kg * 9.81 m/s^2 ?

What is the normal force on the 19 kg box with the 10 kg box sitting on top?
 
it would me greater then the mg right so the Fnet wouldn't be zero?

Would it the normal force of the two boxes or together?
 
If the normal force is greater than the weight of the box, the box will want to travel upward, F = ma and all that.

These types of problems are best analyzed by drawing free body diagrams of the boxes and applying the known forces to them. Once that is accomplished, the equations of equilibrium can be written and solved.
 
SteamKing said:
If the normal force is greater than the weight of the box, the box will want to travel upward, F = ma and all that.

These types of problems are best analyzed by drawing free body diagrams of the boxes and applying the known forces to them. Once that is accomplished, the equations of equilibrium can be written and solved.

so mg would be downward on both of the boxes and the normal force would be upward for both right?
 
so would the normal force being exerted be 98.0N?
 
tristanmagnum said:
so would the normal force being exerted be 98.0N?

Yes.
 
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