What is the Normalisation Constant for an Electron in Spin State?

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SUMMARY

The normalization constant for an electron in the spin state represented by the vector |ψ⟩ = A (3i, 4) is determined to be A = 1/5. This conclusion is reached by ensuring that the wave function integrates to unity, leading to the equation ⟨ψ|ψ⟩ = 1 = 25A². The discussion clarifies that the normalization constant is essential for defining the probability amplitude of the spin state in quantum mechanics.

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ZoroP
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Normalisation constant~ help~~

Homework Statement



An electron is in the spin state |> = A (3i, 4), so determine the normalisation constant A.

Homework Equations



:rolleyes: :frown:

The Attempt at a Solution



:cry: Well, I get confused about this questions, can anybody tell me what the normalisation constant is in this case? And does "in the spin state" mean something for given condition? Thanks a lot.
 
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ZoroP said:

Homework Statement



An electron is in the spin state |> = A (3i, 4), so determine the normalisation constant A.

Homework Equations



:rolleyes: :frown:

The Attempt at a Solution



:cry: Well, I get confused about this questions, can anybody tell me what the normalisation constant is in this case? And does "in the spin state" mean something for given condition? Thanks a lot.
Spin is simply a property that particles posses and this "spin state" describes, well the state of the spin of a particle or system of particles.

As for the question, what does one normally mean when one says a "normalisation constant". What does it mean in the context of a wave function for example?
 


Well, thanks a lot, but i don't think this problem is discussing about wave function, I cannot find any concept about wave function in my lecture notes. Thus, I consider that this question is only about math and calculation. Or maybe you can teach me some about the wave function or any other ideas? Thanks any way~
 


Do you know about complex vectors? And how to normalize those to unit length?
 


yes, o! you mean I can just do it like A = 1/|(3i, 4)|?? Thanks!
 


Yep, that's all there is to it. But don't forget to simplify that expression for A you got now.
 


Thanks, so it's A = 1/5
 


So in Physics we can write the spin state as a function of the particle:

|\psi \rangle = A \left ( \begin{array}{cc} 3i \\ 4 \end{array} \right)

But wave function must integrate to unity over all space, so:

\langle \psi | \psi \rangle = 1 = A^2\left ( \begin{array}{cc} -3i & 4 \end{array} \right) \left ( \begin{array}{cc} 3i \\ 4 \end{array} \right) = 25A^2

So I agree with your answer
 


BerryBoy said:
So in Physics we can write the spin state as a function of the particle:

|\psi \rangle = A \left ( \begin{array}{cc} 3i \\ 4 \end{array} \right)

But wave function must integrate to unity over all space, so:

\langle \psi | \psi \rangle = 1 = A^2\left ( \begin{array}{cc} -3i & 4 \end{array} \right) \left ( \begin{array}{cc} 3i \\ 4 \end{array} \right) = 25A^2

So I agree with your answer


I friggin get it now!
 

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