What is the Parity of a System Described by a Wavefunction?

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Homework Statement


The wavefunction describing state of a system is,
[tex]\psi (r,\theta ,\phi )=\frac{1}{8\sqrt{\pi }}\left( \frac{1}{a_{0}}%<br /> \right) ^{3/2}\frac{r}{a_{0}}e^{-4/2a_{0}}\sin \theta e^{-i\phi }[/tex]
Find the parity of system in this state.


The Attempt at a Solution



[tex]\psi (-r,\theta ,\phi )=\frac{1}{8\sqrt{\pi }}\left( \frac{1}{a_{0}}%<br /> \right) ^{3/2}\frac{-r}{a_{0}}e^{-4/2a_{0}}\sin \theta e^{-i\phi }<br /> =-\psi (r,\theta ,\phi )[/tex]
odd parity.


I'm wrong.But donno where. Pls help.
 
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you mean r →-r ?

Then that gives me the perfect answer.
Thank you very much dear friend.
 
How is that possible?
is it bcz r^2 = x^2+y^2+z^2?
But the reflection changes direction of vector also na?

Can you please explain?