What is the period of function f(x) = -sin(x/5 - pi)?

  • Thread starter Thread starter fr33pl4gu3
  • Start date Start date
  • Tags Tags
    Function Period
Click For Summary

Homework Help Overview

The discussion revolves around determining the period of the function f(x) = -sin(x/5 - pi). Participants are exploring the properties of the sine function and how transformations affect its period.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to identify the period by analyzing the function's transformation and questioning the implications of negative values for period. Some are exploring the relationship between the function's arguments and the sine function's known periods.

Discussion Status

The discussion is active, with various interpretations of the period being explored. Some participants have suggested different values for the period, while others are questioning the validity of those suggestions. There is no explicit consensus yet, but multiple approaches are being discussed.

Contextual Notes

Participants are grappling with the definitions and properties of periodic functions, particularly in relation to phase shifts and transformations of the sine function. There is some confusion regarding the calculations and assumptions about the period.

fr33pl4gu3
Messages
82
Reaction score
0
f(x) = - sin(x/5 - pi)

the period for this is -pi correct, since, k taken out it is 1, and by divide -pi into 1, the answer will be -pi only, correct??
 
Physics news on Phys.org


I don't think you can have a negative period!
To find the period pick a value of x (say zero) and then work out what is the next value of x that will give the same value of f().
Does adding the same constant to both values of X do anything?
 


Does it gives the same pi??
 


So, the answer is "pi"??
 


The period of sin() is pi ie sin(0)=sin(pi)

But in terms of X, since you divide X by 2 what value of X do you need for the function to give the same value as for x=0?
 


What is the exact period of f(x) (in radians)? (Recall p radians is equivalent to 180°; p is obtained by entering: Pi or pi.)

What does the question actually wants anyway?? how to calculate period in radians.
 


zero??
 


mgb_phys said:
The period of sin() is pi ie sin(0)=sin(pi)

This is not correct. A function [itex]f(x)[/itex] is periodic with period [itex]p[/itex] if
[tex]f(x+p)=f(x)[/tex]
for all real [itex]x[/itex]. For [itex]\sin(x)[/itex], this is true for [itex]p=2\pi[/itex], and not true for [itex]p=\pi[/itex], because [itex]\sin(x+\pi)=-\sin(x)[/itex], not [itex]\sin(x)[/itex].
 


yes, and the answer is 10pi, by getting the 2pi divide 1/5 to get the answer. I get confuse that i need to multiply by 5 so to get b=5, but when i try 1/5, it's done.
 
  • #10


fr33pl4gu3 said:
yes, and the answer is 10pi

Correct!
 
  • #11


in this function, f(x) = - sin(x/5 - pi), the -pi would be a phase shift.

In general for sin (wt + q), w = 2pi f = 2 pi/T, where T is the period, and q is the phase shift.
 
  • #12


mgb_phys said:
The period of sin() is pi ie sin(0)=sin(pi)

But in terms of X, since you divide X by 2 what value of X do you need for the function to give the same value as for x=0?

No, the period of sin(x) is 2pi.

fr33pl4gu3. your function is -sin(x/5- pi). When x/5- pi= 0, what is x? When x/5- pi= 2pi, what is x? The difference between those is the period.
 

Similar threads

Replies
3
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
15
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
3K